14 【程序 14 求日期】
题目：输入某年某月某日，判断这一天是这一年的第几天？
程序分析：以 3 月 5 日为例，应该先把前两个月的加起来，然后再加上 5 天即本年的第几天，特殊情况， 闰年且输入月份大于 3 时需考虑多加一天。
package cskaoyan;public class cskaoyan14 {
private static int year = 0;
private static int month = 0;
private static int day = 0;
private static int[] leapYear = { 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
private static int[] commonYear = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
private int sum = 0;@org.junit.Test
public void date() {
java.util.Scanner in = new java.util.Scanner(System.in);
year = in.nextInt();
month = in.nextInt();
day = in.nextInt();try {
if (verify(year, month, day)) {
if (leapYear(year)) {
for (int i = 0; i < month - 1; i++) {
sum += leapYear[i];
}
} else {
for (int i = 0; i < month - 1; i++) {
sum += commonYear[i];
}
}sum += day;System.out.println(year + "年" + month + "月" + day + "日" + "是这一年的第" + sum + "天");
}
} catch (Throwable e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
in.close();
}
}private static boolean verify(int yaer, int month, int day) throws Throwable {
if (year < 1) {
throw new Exception("YEAR ERROR");
}if (month < 1 || month > 12) {
throw new Exception("MONTH ERROR");
}if (day < 1 || day > 31) {
throw new Exception("DAY ERROR");
}if (month == 4 || month == 6 || month == 9 || month == 11) {
if (day > 30) {
throw new Exception("DAY ERROR");
}
}if (month == 2) {
if (leapYear(year)) {
if (day > 29) {
throw new Exception("DAY ERROR");
}
} else {
if (day > 28) {
throw new Exception("DAY ERROR");
}
}
}return true;
}private static boolean leapYear(int year) {
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0 && year % 3200 != 0)) {
return true;
} else {
return false;
}
}
}
