Two Sum IV – Input is a BST

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.

Example 1:

Input:
    5
   / \
  3   6
 / \   \
2   4   7Target = 9Output: True

Example 2:

Input:
    5
   / \
  3   6
 / \   \
2   4   7Target = 28Output: False

 思路：把值放入map中，遍历值，并判断另一个组合数是否在map中即可。JAVA CODE

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    Map<Integer,Integer> map = new HashMap<>();
    int key = 0;
    public boolean findTarget(TreeNode root, int k) {
        // Queue<TreeNode> queue = new ArrayDeque<>();
        // queue.offer(root);
        // while(!queue.isEmpty()){
        //     root =
        //     if()
        // }
        find(root);
        for (Integer value : map.values()) {
            if(value*2!=k&&map.containsValue(k - value.intValue()))
                return true;
        }
        return false;
    }
    void find(TreeNode rr){
         if(rr != null){
         find(rr.left);
         map.put(new Integer(key++), new Integer(rr.val));
         find(rr.right);
        }
    }
}