首页 技术 正文
技术 2022年11月17日
0 收藏 359 点赞 3,175 浏览 3218 个字

Wall

Time Limit: 1000MS Memory Limit: 10000K

Total Submissions: 32360 Accepted: 10969

Description

Once upon a time there was a greedy King who ordered his chief Architect to build a wall around the King’s castle. The King was so greedy, that he would not listen to his Architect’s proposals to build a beautiful brick wall with a perfect shape and nice tall towers. Instead, he ordered to build the wall around the whole castle using the least amount of stone and labor, but demanded that the wall should not come closer to the castle than a certain distance. If the King finds that the Architect has used more resources to build the wall than it was absolutely necessary to satisfy those requirements, then the Architect will loose his head. Moreover, he demanded Architect to introduce at once a plan of the wall listing the exact amount of resources that are needed to build the wall.

Your task is to help poor Architect to save his head, by writing a program that will find the minimum possible length of the wall that he could build around the castle to satisfy King’s requirements.

The task is somewhat simplified by the fact, that the King’s castle has a polygonal shape and is situated on a flat ground. The Architect has already established a Cartesian coordinate system and has precisely measured the coordinates of all castle’s vertices in feet.

Input

The first line of the input file contains two integer numbers N and L separated by a space. N (3 <= N <= 1000) is the number of vertices in the King’s castle, and L (1 <= L <= 1000) is the minimal number of feet that King allows for the wall to come close to the castle.

Next N lines describe coordinates of castle’s vertices in a clockwise order. Each line contains two integer numbers Xi and Yi separated by a space (-10000 <= Xi, Yi <= 10000) that represent the coordinates of ith vertex. All vertices are different and the sides of the castle do not intersect anywhere except for vertices.

Output

Write to the output file the single number that represents the minimal possible length of the wall in feet that could be built around the castle to satisfy King’s requirements. You must present the integer number of feet to the King, because the floating numbers are not invented yet. However, you must round the result in such a way, that it is accurate to 8 inches (1 foot is equal to 12 inches), since the King will not tolerate larger error in the estimates.

Sample Input

9 100

200 400

300 400

300 300

400 300

400 400

500 400

500 200

350 200

200 200

Sample Output

1628

Hint

结果四舍五入就可以了

Source

Northeastern Europe 2001

#include <iostream>
#include <cstdio>
#include <cmath>
#include <stack>
#include <algorithm>
using namespace std;const int INF = 0x3f3f3f3f;const double Pi = 3.141592654;struct node
{
int x;
int y;
} P[500000],S[500000];int det(int x1,int y1,int x2,int y2)
{
return x1*y2-x2*y1;
}int cross(node a,node b,node c)
{
return det(b.x-a.x,b.y-a.y,c.x-a.x,c.y-a.y);
}
int dis(node a,node b)
{
return (a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y);
}bool cmp(node a, node b)
{
int k=cross(P[0],a,b);
if(k>0)
{
return true;
}
if(k==0&&dis(a,P[0])<dis(b,P[0]))
{
return true;
}
return false;
}int main()
{
int n,m;
int x,y,flag;
while(~scanf("%d %d",&n,&m))
{
x=INF;
y=INF;
flag=0;
for(int i=0; i<n; i++)
{
scanf("%d %d",&P[i].x,&P[i].y);
if(y>P[i].y)
{
x=P[i].x;
y=P[i].y;
flag=i;
}
else if(y==P[i].y&&x>P[i].x)
{
x=P[i].x;
flag=i;
}
} node temp=P[flag];
P[flag]=P[0];
P[0]=temp;
int top=0;
if(n==2)
{
S[0]=P[0];
S[1]=P[1];
S[2]=S[0];
top=2;
}
else if(n>2)
{
sort(P+1,P+n,cmp);
P[n]=P[0];
for(int i=0; i<2; i++)
{
S[top++]=P[i];
}
top=1;
for(int i=2; i<=n; i++)
{
while(top>=1&&cross(S[top-1],S[top],P[i])<=0)
{
top--;
}
S[++top]=P[i];
}
}
double MaxDis=0;
for(int i=0; i<top; i++)
{
MaxDis+=sqrt(dis(S[i],S[i+1]));
}
MaxDis+=2*m*Pi;
printf("%.0f\n",MaxDis);
}
return 0;
}
相关推荐
python开发_常用的python模块及安装方法
adodb:我们领导推荐的数据库连接组件bsddb3:BerkeleyDB的连接组件Cheetah-1.0:我比较喜欢这个版本的cheeta…
日期:2022-11-24 点赞:878 阅读:9,086
Educational Codeforces Round 11 C. Hard Process 二分
C. Hard Process题目连接:http://www.codeforces.com/contest/660/problem/CDes…
日期:2022-11-24 点赞:807 阅读:5,561
下载Ubuntn 17.04 内核源代码
zengkefu@server1:/usr/src$ uname -aLinux server1 4.10.0-19-generic #21…
日期:2022-11-24 点赞:569 阅读:6,410
可用Active Desktop Calendar V7.86 注册码序列号
可用Active Desktop Calendar V7.86 注册码序列号Name: www.greendown.cn Code: &nb…
日期:2022-11-24 点赞:733 阅读:6,183
Android调用系统相机、自定义相机、处理大图片
Android调用系统相机和自定义相机实例本博文主要是介绍了android上使用相机进行拍照并显示的两种方式,并且由于涉及到要把拍到的照片显…
日期:2022-11-24 点赞:512 阅读:7,820
Struts的使用
一、Struts2的获取  Struts的官方网站为:http://struts.apache.org/  下载完Struts2的jar包,…
日期:2022-11-24 点赞:671 阅读:4,903