1.02-get-params

import urllib.request
import urllib.parse
import stringdef get_method_params():    url = "http://www.baidu.com/s?wd="
    #拼接字符串(汉字)
    #python可以接受的数据
    #https://www.baidu.com/s?wd=%E7%BE%8E%E5%A5%B3    name = "美女"
    final_url = url+name
    print(final_url)
    #代码发送了请求
    #网址里面包含了汉字;ascii是没有汉字的;url转译
    #将包含汉字的网址进行转译
    encode_new_url = urllib.parse.quote(final_url,safe=string.printable)
    print(encode_new_url)
    # 使用代码发送网络请求
    response = urllib.request.urlopen(encode_new_url)
    print(response)
    #读取内容
    data = response.read().decode()
    print(data)
    #保存到本地
    with open("02-encode.html","w",encoding="utf-8")as f:
        f.write(data)
    #UnicodeEncodeError: 'ascii' codec can't encode
    # characters in position 10-11: ordinal not in range(128)
    #python:是解释性语言;解析器只支持 ascii 0 - 127
    #不支持中文get_method_params()