POJ3204+DInic+maxflow

Dinic+maxflow
题意：找这样一种边的个数，就是增加该边的容量，可以使得最大流变大
思路：求maxflow，再枚举流量为0的边，增加容量，看是否能找到增广路径。

 /*
 Dinic+maxflow
 题意：找这样一种边的个数，就是增加该边的容量，可以使得最大流变大
 思路：求maxflow，再枚举流量为0的边，增加容量，看是否能找到增广路径。
 */
 #include<stdio.h>
 #include<string.h>
 #include<stdlib.h>
 #include<algorithm>
 #include<iostream>
 #include<queue>
 #include<map>
 #include<stack>
 #include<set>
 #include<math.h>
 using namespace std;
 typedef long long int64;
 //typedef __int64 int64;
 typedef pair<int64,int64> PII;
 #define MP(a,b) make_pair((a),(b))
 const int maxn = ;
 const int maxm = ;
 const int inf = 0x3f3f3f3f;
 const double pi=acos(-1.0);
 const double eps = 1e-; struct Edge{
     int u,v,next,val;
     bool flag;
 }edge[ maxm<< ];
 int cnt,head[ maxn ];
 int vis[ maxn ];
 int lev[ maxn ];
 int q[ maxn<< ]; void init(){
     cnt = ;
     memset( head,-,sizeof( head ) );
 }
 void addedge( int a,int b,int c ){
     edge[ cnt ].u = a;
     edge[ cnt ].v = b;
     edge[ cnt ].val = c;
     edge[ cnt ].next = head[ a ];
     if( cnt%== ) edge[ cnt ].flag = true;
     else edge[ cnt ].flag = false;
     head[ a ] = cnt ++;
 } bool bfs( int n,int start,int end ){
     int head2 = ,tail2 = ;
     q[ tail2++ ] = start;
     memset( lev,-,sizeof( lev ) );
     lev[ start ] = ;
     while( head2<tail2 ){
         int u = q[ head2++ ];
         for( int i=head[u];i!=-;i=edge[i].next ){
             int v = edge[i].v;
             if( edge[i].val>&&lev[v]==- ){
                 lev[v] = lev[u]+;
                 q[ tail2++ ] = v;
             }
         }
     }
     if( lev[ end ]==- ) return false;
     else return true;
 } int Dinic( int n,int start,int end ){
     int maxflow = ;
     while( true ){
         if( bfs(n,start,end )==false ) break;
         int id = start;
         int tail = ;
         while( true ){
             if( id==end ){
                 int flow = inf;
                 int flag = -;
                 for( int i=;i<tail;i++ ){
                     if( edge[ q[i] ].val<flow ){
                         flow = edge[ q[i] ].val ;
                         flag = i;
                     }
                 }
                 for( int i=;i<tail;i++ ){
                     edge[ q[i] ].val -= flow;
                     edge[ q[i]^ ].val += flow;
                 }
                 if( flag!=- ){
                     maxflow += flow;
                     tail = flag;
                     id = edge[ q[flag] ].u;
                 }
                 else
                     return inf;
             }
             id = head[ id ];
             while( id!=- ){
                 if( edge[id].val>&&lev[edge[id].u]+==lev[edge[id].v] ){
                     break;
                 }
                 id = edge[ id ].next;
             }
             if( id!=- ){
                 q[ tail++ ] = id;
                 id = edge[ id ].v;
             }
             else{
                 if( tail== ) break;
                 lev[ edge[q[tail-]].v ] = -;
                 id = edge[ q[--tail] ].u;
             }
         }
     }
     return maxflow;
 }                  int main(){
     int n,m;
     while( scanf("%d%d",&n,&m)== ){
         init();
         int a,b,c;
         int start = ;
         int end = n-;
         for( int i=;i<m;i++ ){
             scanf("%d%d%d",&a,&b,&c);
             addedge( a,b,c );
             addedge( b,a, );
         }
         Dinic( n,start,end );
         int ans = ;
         for( int i=;i<cnt;i++ ){
             if( edge[i].val==&&edge[i].flag==true ){
                 edge[i].val ++ ;
                 if( bfs( n,start,end )==true ){
                     ans ++ ;
                 }
                 edge[i].val -- ;
             }
         }
         printf("%d\n",ans);
     }
     return ;
 }