下次不要被长题目吓到，其实不一定难。
先看输入输出，再揣测题意。
原文：
2548. Celebrity jeopardy
Time Limit: 1.0 Seconds Memory Limit: 65536K
Total Runs: 1306 Accepted Runs: 898
It’s hard to construct a problem that’s so easy that everyone
will get it, yet still difficult enough to be worthy of some respect. Usually,
we err on one side or the other. How simple can a problem really be?
Here, as in Celebrity Jepoardy, questions and answers are a bit confused,
and, because the participants are celebrities, there’s a real need to make the
challenges simple. Your program needs to prepare a question to be solved — an
equation to be solved — given the answer. Specifically, you have to write a
program which finds the simplest possible equation to be solved given the
answer, considering all possible equations using the standard mathematical
symbols in the usual manner. In this context, simplest can be defined
unambiguously several different ways leading to the same path of resolution. For
now, find the equation whose transformation into the desired answer requires the
least effort.
For example, given the answer X = 2, you might create the equation 9 – X = 7.
Alternately, you could build the system X > 0; X^2 = 4. These may not be the
simplest possible equations. Solving these mind-scratchers might be hard for a
celebrity.
Input
Each input line contains a solution in the form <symbol> =
<value>
Output
For each input line, print the simplest system of equations which would to
lead to the provided solution, respecting the use of space exactly as in the
input.
Sample Input
Y = 3
X=9
Sample Output
Y = 3
X=9
Source: Southeastern
European 2006
源代码：
#include <iostream>
#include <string>
using namespace std; int main() {
string aaa;
while (getline(cin, aaa)) {
cout << aaa << endl;
}
return ;
}
