首页 技术 正文
技术 2022年11月21日
0 收藏 825 点赞 3,609 浏览 2511 个字

After each PAT, the PAT Center will announce the ranking of institutions based on their students’ performances. Now you are asked to generate the ranklist.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤10^5), which is the number of testees. Then N lines follow, each gives the information of a testee in the following format:

ID Score School

where ID is a string of 6 characters with the first one representing the test level: B stands for the basic level, A the advanced level and T the top level; Score is an integer in [0, 100]; and School is the institution code which is a string of no more than 6 English letters (case insensitive). Note: it is guaranteed that ID is unique for each testee.

Output Specification:

For each case, first print in a line the total number of institutions. Then output the ranklist of institutions in nondecreasing order of their ranks in the following format:

Rank School TWS Ns

where Rank is the rank (start from 1) of the institution; School is the institution code (all in lower case); ; TWS is the total weighted score which is defined to be the integer part of ScoreB/1.5 + ScoreA + ScoreT*1.5, where ScoreX is the total score of the testees belong to this institution on level X; and Ns is the total number of testees who belong to this institution.

The institutions are ranked according to their TWS. If there is a tie, the institutions are supposed to have the same rank, and they shall be printed in ascending order of Ns. If there is still a tie, they shall be printed in alphabetical order of their codes.

Sample Input:

10

A57908 85 Au

B57908 54 LanX

A37487 60 au

T28374 67 CMU

T32486 24 hypu

A66734 92 cmu

B76378 71 AU

A47780 45 lanx

A72809 100 pku

A03274 45 hypu

Sample Output:

5

1 cmu 192 2

1 au 192 3

3 pku 100 1

4 hypu 81 2

4 lanx 81 2

#include<iostream> //海星
#include<unordered_map>
#include<string>
#include<vector>
#include<algorithm>
using namespace std;
struct node{
string code;
int n, tws=0;
int s[3]={0};
node(string c):code(c), n(1), tws(0){
}
};
unordered_map<string, int> m;
bool cmp(const node& a, const node& b){
if(a.tws!=b.tws) return a.tws>b.tws;
else if(a.n!=b.n) return a.n<b.n;
else return a.code<b.code;
}
int main(){
int n, cnt=1;
cin>>n;
vector<node> v;
for(int i=0; i<n; i++){
string id, code;
int s, t;
cin>>id>>s>>code;
for(int j=0; j<code.size(); j++)
code[j]=tolower(code[j]);
if(id[0]=='B') t=0;
else if(id[0]=='A') t=1;
else t=2;
if(m[code]==0){
node temp(code);
temp.s[t]=s;
v.push_back(temp);
m[code]=cnt;
cnt++;
}else{
v[m[code]-1].n++;
v[m[code]-1].s[t]+=s;
}
}
for(int i=0; i<v.size(); i++)
v[i].tws=v[i].s[0]/1.5+v[i].s[1]+v[i].s[2]*1.5;
sort(v.begin(), v.end(), cmp);
cout<<v.size()<<endl;
int lastrank=1;
cout<<1<<" "<<v[0].code<<" "<<v[0].tws<<" "<<v[0].n<<endl;
for(int i=1; i<v.size(); i++){
if(v[i].tws!=v[i-1].tws)
lastrank=i+1;
cout<<lastrank<<" "<<v[i].code<<" "<<v[i].tws<<" "<<v[i].n<<endl;
}
return 0;
}
相关推荐
python开发_常用的python模块及安装方法
adodb:我们领导推荐的数据库连接组件bsddb3:BerkeleyDB的连接组件Cheetah-1.0:我比较喜欢这个版本的cheeta…
日期:2022-11-24 点赞:878 阅读:8,960
Educational Codeforces Round 11 C. Hard Process 二分
C. Hard Process题目连接:http://www.codeforces.com/contest/660/problem/CDes…
日期:2022-11-24 点赞:807 阅读:5,484
下载Ubuntn 17.04 内核源代码
zengkefu@server1:/usr/src$ uname -aLinux server1 4.10.0-19-generic #21…
日期:2022-11-24 点赞:569 阅读:6,330
可用Active Desktop Calendar V7.86 注册码序列号
可用Active Desktop Calendar V7.86 注册码序列号Name: www.greendown.cn Code: &nb…
日期:2022-11-24 点赞:733 阅读:6,113
Android调用系统相机、自定义相机、处理大图片
Android调用系统相机和自定义相机实例本博文主要是介绍了android上使用相机进行拍照并显示的两种方式,并且由于涉及到要把拍到的照片显…
日期:2022-11-24 点赞:512 阅读:7,745
Struts的使用
一、Struts2的获取  Struts的官方网站为:http://struts.apache.org/  下载完Struts2的jar包,…
日期:2022-11-24 点赞:671 阅读:4,779