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技术 2022年11月7日
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将另外一个类嵌入到另外一个类 从而合并生成一张表

Husband.java

package com.bjsxt.hibernate;import javax.persistence.Embedded;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.JoinColumns;
import javax.persistence.OneToOne;@Entity
public class Husband {
private int id;
private String name;
private Wife wife;
@Id
@GeneratedValue
public int getId() {
return id;
} public String getName() {
return name;
}
@Embedded
public Wife getWife() {
return wife;
}
public void setId(int id) {
this.id = id;
}
public void setName(String name) {
this.name = name;
}
public void setWife(Wife wife) {
this.wife = wife;
}}

wifi.java

package com.bjsxt.hibernate;public class Wife {    private String wifeName;
private int age; public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
} public String getWifeName() {
return wifeName;
}
public void setWifeName(String name) {
this.wifeName = name;
}}

使用Xml

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"><hibernate-mapping>
<class name="com.bjsxt.hibernate.Husband" >
<id name="id">
<generator class="native"></generator>
</id> <property name="name"></property>
<component name="wife">
<property name="wifeName"></property>
<property name="age"></property>
</component>
</class></hibernate-mapping>

测试

    @Test
public void testSchemaExport() {
new SchemaExport(new AnnotationConfiguration().configure()).create(false, true);
}
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