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技术 2022年11月7日
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Design a data structure that supports the following two operations: addWord(word) and search(word)

search(word) can search a literal word or a regular expression string containing only letters a-z or ..

A . means it can represent any one letter.
Notice

You may assume that all words are consist of lowercase letters a-z.
Example

addWord(“bad”)
addWord(“dad”)
addWord(“mad”)
search(“pad”)  // return false
search(“bad”)  // return true
search(“.ad”)  // return true
search(“b..”)  // return true

LeetCode上的原题,请参见我之前的博客Add and Search Word – Data structure design

class WordDictionary {
public:
struct TrieNode {
bool isLeaf;
TrieNode *child[];
}; WordDictionary() {
root = new TrieNode();
} // Adds a word into the data structure.
void addWord(string word) {
TrieNode *p = root;
for (char c : word) {
int i = c - 'a';
if (!p->child[i]) p->child[i] = new TrieNode();
p = p->child[i];
}
p->isLeaf = true;
} // Returns if the word is in the data structure. A word could
// contain the dot character '.' to represent any one letter.
bool search(string word) {
search(word, root, );
} bool search(string &word, TrieNode *p, int i) {
if (i == word.size()) return p->isLeaf;
if (word[i] == '.') {
for (auto a : p->child) {
if (a && search(word, a, i + )) return true;
}
return false;
} else {
return p->child[word[i] - 'a'] && search(word, p->child[word[i] - 'a'], i + );
}
}private:
TrieNode *root;
};
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