首页 技术 正文
技术 2022年11月8日
0 收藏 605 点赞 1,875 浏览 1400 个字

You are playing the following Bulls and Cows game with your friend: You write a 4-digit secret number and ask your friend to guess it. Each time your friend guesses a number, you give a hint. The hint tells your friend how many digits are in the correct positions (called “bulls”) and how many digits are in the wrong positions (called “cows”). Your friend will use those hints to find out the secret number.

For example:

Secret number:  "1807"
Friend's guess: "7810"

Hint: 1 bull and 3 cows. (The bull is 8, the cows are 01 and 7.)

Write a function to return a hint according to the secret number and friend’s guess, use A to indicate the bulls and B to indicate the cows. In the above example, your function should return "1A3B".

Please note that both secret number and friend’s guess may contain duplicate digits, for example:

Secret number:  "1123"
Friend's guess: "0111"

In this case, the 1st 1 in friend’s guess is a bull, the 2nd or 3rd 1 is a cow, and your function should return "1A1B".

You may assume that the secret number and your friend’s guess only contain digits, and their lengths are always equal.

Solution:

http://www.bubuko.com/infodetail-1174728.html

https://leetcode.com/discuss/67031/one-pass-java-solution

 public class Solution {
public String getHint(String secret, String guess) {
int bulls = 0;
int cows = 0;
int[] nums = new int[10];
for(int i = 0; i < secret.length(); ++i) {
if(secret.charAt(i) == guess.charAt(i))
bulls++;
else {
if(nums[secret.charAt(i) - '0'] < 0)
cows++;
if(nums[guess.charAt(i) - '0'] > 0)
cows++;
nums[secret.charAt(i) - '0']++;
nums[guess.charAt(i) - '0']--;
}
}
return bulls + "A" + cows + "B";
}
}
相关推荐
python开发_常用的python模块及安装方法
adodb:我们领导推荐的数据库连接组件bsddb3:BerkeleyDB的连接组件Cheetah-1.0:我比较喜欢这个版本的cheeta…
日期:2022-11-24 点赞:878 阅读:9,086
Educational Codeforces Round 11 C. Hard Process 二分
C. Hard Process题目连接:http://www.codeforces.com/contest/660/problem/CDes…
日期:2022-11-24 点赞:807 阅读:5,561
下载Ubuntn 17.04 内核源代码
zengkefu@server1:/usr/src$ uname -aLinux server1 4.10.0-19-generic #21…
日期:2022-11-24 点赞:569 阅读:6,410
可用Active Desktop Calendar V7.86 注册码序列号
可用Active Desktop Calendar V7.86 注册码序列号Name: www.greendown.cn Code: &nb…
日期:2022-11-24 点赞:733 阅读:6,183
Android调用系统相机、自定义相机、处理大图片
Android调用系统相机和自定义相机实例本博文主要是介绍了android上使用相机进行拍照并显示的两种方式,并且由于涉及到要把拍到的照片显…
日期:2022-11-24 点赞:512 阅读:7,820
Struts的使用
一、Struts2的获取  Struts的官方网站为:http://struts.apache.org/  下载完Struts2的jar包,…
日期:2022-11-24 点赞:671 阅读:4,903