Potato Sacks

开发者奕冉技术 2022年11月9日

0 收藏 399 点赞 4,017 浏览 1324 个字

Potato sacks come in different weight capacities (specified in pounds). Potatoes come in different weights. If you are given some number of potatoes of possibly different weights (specified in pounds), determine if it is possible to exactly fill a potato sack of a given capacity using some or all of the potatoes.

Input

The first line of input contains a single decimal integer P, (1≤P≤100), which is the number of data sets that follow. Each data set should be processed identically and independently.

Each data set consists of a single line of input containing 12 space separated positive integers. They are the data set number, K, followed by the capacity, CC, of the potato sack in pounds, (10≤C≤30),

followed by the weights of 10 potatoes in pounds. A potato will not weigh more than 3 pounds.

Output

For each data set there is a single line of output.

The output line consists of the data set number, K, followed by a single space, the word “YES” if the potato sack can be filled exactly to capacity C pounds or the word “NO” if it cannot be filled exactly.

样例输出

　2

1 20 3 2 1 3 3 2 3 2 1 1
2 25 3 3 3 3 3 3 3 3 3 3

样例输出

　1 YES

2 NOidea: 简单来说，判断能否从这么多数中找能组成一个数

#include <iostream>
#include <cstring>
using namespace std;
int n, ans, k;
int a[];
bool dfs(int i, int sum)
{
    if(i==)
        return sum==ans;
    if(dfs(i+, sum))
        return true;
    if(dfs(i+, sum+a[i]))
        return true;
    return false;
}
int main()
{
    cin >> n;
    for(int i=;i<=n;i++)
    {
        cin >> k >> ans;
        for(int j=;j<;j++)
        {
            cin >> a[j];
        }
        if(dfs(, ))
            printf("%d YES\n",k);
        else
            printf("%d NO\n",k);
    }
}