#有五个数字:1、2、3、4、5,能组成多少个互不相同且无重复数字的四位数?各是多少?
e =[]
for a in range(1,6):
for b in range(1,6):
for c in range(1,6):
for d in range(1,6):
if a!=b and a!=c and a!=d and b!=c and b!=d and c!=d:
e.append(str(a)+str(b)+str(c)+str(d))
print("组成数量:%d" %len(e))
print(e)
运行结果: