# encoding:utf-8
# p001_1234threeNums.pydef threeNums():
'''题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？'''
print None
count = 0
nums = []
for index1 in xrange(1,5):
for index2 in xrange(1,5):
for index3 in xrange(1,5):
if index1 != index2 and index1 != index3 and index2 != index3:
num = 100 * index1 + 10 * index2 + index3
if num not in nums:
nums.append(num)
count += 1
print count
print nums# threeNums()
# 在四个数中任意剔除一个，剩下三个的所有组合 --- 没完成，待完善
def threeNums_method1():
'''take out a digit from the four digits'''
L = [i for i in xrange(1,5)]
print L
cnt = 0
for index in xrange(4):
L1 = L[:]
del L1[index]
for index1 in xrange(3):
print '%d%d%d'%(L1[index1%3],L1[(index1+1)%3],L1[(index1+2)%3])
cnt += 1
print 'count : %d'%cntthreeNums_method1()################################################################
# 最简单方法
print [(x, y, z) for x in xrange(1,5) for y in xrange(1,5) for z in xrange(1,5) if ((x != y) and (y != z) and (x != z))]
