–case when 经典用法
SELECT * FROM
(SELECT 1 NUM,
‘奖项金额’,
SUM(CASE WHEN DJMC= ‘一等奖’ AND CGBZ=0 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘二等奖’ AND CGBZ=0 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘三等奖’ AND CGBZ=0 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘四等奖’ AND CGBZ=0 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘五等奖’ AND CGBZ=0 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘一等奖’ AND CGBZ=1 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘二等奖’ AND CGBZ=1 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘三等奖’ AND CGBZ=1 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘四等奖’ AND CGBZ=1 THEN DJJE ELSE 0 END) ,
SUM(CASE WHEN DJMC= ‘五等奖’ AND CGBZ=1 THEN DJJE ELSE 0 END)
FROM XXDZMX T WHERE DZYF=20111129 AND ZFLX=0
UNION ALL
SELECT 2 NUM,
‘奖项数量’,
SUM(CASE WHEN DJMC= ‘一等奖’ AND CGBZ=0 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘二等奖’ AND CGBZ=0 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘三等奖’ AND CGBZ=0 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘四等奖’ AND CGBZ=0 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘五等奖’ AND CGBZ=0 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘一等奖’ AND CGBZ=1 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘二等奖’ AND CGBZ=1 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘三等奖’ AND CGBZ=1 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘四等奖’ AND CGBZ=1 THEN 1 ELSE 0 END),
SUM(CASE WHEN DJMC= ‘五等奖’ AND CGBZ=1 THEN 1 ELSE 0 END)
FROM XXDZMX T WHERE DZYF=20111129 AND ZFLX=0
) ORDER BY NUM;
–结果如下：
— 1 奖项金额 0 50 10 0 2 200 0 10 5 2
— 2 奖项数量 0 1 1 0 1 1 0 1 1 1
–初始数据如下：
SELECT ZJJX, SUM(CGSL), SUM(CGJEH), SUM(SBSL), SUM(SBJEH)
FROM (
SELECT ZJJX, COUNT(ZJJE) CGSL, SUM(ZJJE) CGJEH, 0 SBSL, 0 SBJEH FROM YW_ZJFPJL where substr(to_char(zjsj, ‘yyyy-mm-dd hh24:mi:ss’), 0, 7) = ‘2016-10’ GROUP BY ZJJX
UNION ALL
SELECT ZJJX, 0 CGSL, 0 CGJEH, COUNT(ZJJE) SBSL, SUM(ZJJE) SBJEH FROM YW_FJCWJL where substr(to_char(zjsj, ‘yyyy-mm-dd hh24:mi:ss’), 0, 7) = ‘2016-10’ GROUP BY ZJJX)
GROUP BY ZJJX;
/*
一等奖 1 200 0 0
三等奖 16 160 5 50
四等奖 28 140 23 115
五等奖 52 104 33 66
*/
–以下sql完成的哦
–奖项金额完成的
SELECT *
FROM (SELECT ‘奖项金额(成功)’,
SUM(CASE WHEN ZJJX = ‘一等奖’ THEN SUM(ZJJE) ELSE 0 END) 一等奖成功金额,
SUM(CASE WHEN ZJJX = ‘二等奖’ THEN SUM(ZJJE) ELSE 0 END) 二等奖成功金额,
SUM(CASE WHEN ZJJX = ‘三等奖’ THEN SUM(ZJJE) ELSE 0 END) 三等奖成功金额,
SUM(CASE WHEN ZJJX = ‘四等奖’ THEN SUM(ZJJE) ELSE 0 END) 四等奖成功金额,
SUM(CASE WHEN ZJJX = ‘五等奖’ THEN SUM(ZJJE) ELSE 0 END) 五等奖成功金额
FROM YW_ZJFPJL T WHERE to_char(zjsj,’yyyymmdd’)=’20161017′ GROUP BY ZJJX),
(SELECT ‘奖项金额(失败)’,
SUM(CASE WHEN ZJJX = ‘一等奖’ THEN SUM(ZJJE) ELSE 0 END) 一等奖失败金额,
SUM(CASE WHEN ZJJX = ‘二等奖’ THEN SUM(ZJJE) ELSE 0 END) 二等奖失败金额,
SUM(CASE WHEN ZJJX = ‘三等奖’ THEN SUM(ZJJE) ELSE 0 END) 三等奖失败金额,
SUM(CASE WHEN ZJJX = ‘四等奖’ THEN SUM(ZJJE) ELSE 0 END) 四等奖失败金额,
SUM(CASE WHEN ZJJX = ‘五等奖’ THEN SUM(ZJJE) ELSE 0 END) 五等奖失败金额
FROM YW_FJCWJL T WHERE to_char(zjsj,’yyyymmdd’)=’20161017′
GROUP BY ZJJX);
–输出结果： 1 奖项金额(成功) 200 0 160 140 104 奖项金额(失败) 0 0 50 115 66
–奖项数量完成的
SELECT * FROM
(SELECT ‘奖项数量(成功)’,
SUM(CASE WHEN ZJJX = ‘一等奖’ THEN COUNT(ZJJE) ELSE 0 END) 一等奖成功数量,
SUM(CASE WHEN ZJJX = ‘二等奖’ THEN COUNT(ZJJE) ELSE 0 END) 二等奖成功数量,
SUM(CASE WHEN ZJJX = ‘三等奖’ THEN COUNT(ZJJE) ELSE 0 END) 三等奖成功数量,
SUM(CASE WHEN ZJJX = ‘四等奖’ THEN COUNT(ZJJE) ELSE 0 END) 四等奖成功数量,
SUM(CASE WHEN ZJJX = ‘五等奖’ THEN COUNT(ZJJE) ELSE 0 END) 五等奖成功数量
FROM YW_ZJFPJL T WHERE to_char(zjsj,’yyyymmdd’)=’20161017′ GROUP BY ZJJX),
(SELECT ‘奖项数量(失败)’,
SUM(CASE WHEN ZJJX = ‘一等奖’ THEN COUNT(ZJJE) ELSE 0 END) 一等奖失败数量,
SUM(CASE WHEN ZJJX = ‘二等奖’ THEN COUNT(ZJJE) ELSE 0 END) 二等奖失败数量,
SUM(CASE WHEN ZJJX = ‘三等奖’ THEN COUNT(ZJJE) ELSE 0 END) 三等奖失败数量,
SUM(CASE WHEN ZJJX = ‘四等奖’ THEN COUNT(ZJJE) ELSE 0 END) 四等奖失败数量,
SUM(CASE WHEN ZJJX = ‘五等奖’ THEN COUNT(ZJJE) ELSE 0 END) 五等奖失败数量
FROM YW_FJCWJL T WHERE to_char(zjsj,’yyyymmdd’)=’20161017′
GROUP BY ZJJX);
–输出结果： 奖项数量(成功) 1 0 16 28 52 奖项数量(失败) 0 0 5 23 33
