#include <stdio.h>
#include <stdlib.h>
typedef long long ll; int main()
{
ll x=1e17;
ll y=1e18;
ll a,b;
scanf("%lld",&a);
//long long 范围 <大约为9.2*10^18 (2^63)
//x=1e17
//1<=a<=10^18
///所以 b=((5*(x*9%a))%a*18)%a; 是不对的,中间运算结构xx*10^18已超出整形范围(2^63)
///1~10^18-1 b
///1~10^18 b+1
///k~10^18+k-1 b+k(=a)
b=((x**)%a*)%a;
printf("%lld %lld\n",a-b,y+a-b-); return ;
}